Are your front axleshafts U-joint or 5 balls or birfield?

U joint.

NO need for the massive amount of grease in those knuckles then.

Ujoint axles hold grease very well. Its the old 5 ball and the newer birfieds that are exposed inside the knuckle cavity and need lubrication.

Steering knuckles including kingpins
tierod and drag link
drivehsaft ujoints (6 of them)
steering ujoints (2 I think)
wheel bearings (12 total, 6 hubs)
Misc suspension/leaf bushings
pintle swivel

What else gets grease?

Other than the steering knuckles and the wheel bearings all the rest of that just gets a few pumps.

On these rigs, it's supposed to encapsulate the entire thing, with a rubber boot for protection, so you're filling the entire knuckle housing and not just the U-joint zerks themselves. There are 2 plugs, each gets removed when putting grease into their corresponding zerk. 3-4 lbs is expected per knuckle.

I know all too well. Ive owned several. 2.5 and 5 ton. I even have set of rockwells and 16.00s under one of my chevy pickups. I have several toploaders out here in the parts pile.

Rebuilt tons of them over the years. Literally TONS of them since a pair of 2.5s is around 1200lbs and 5 tons are around 3000lbs, lol!

The ujoinys just sit in there and dont actually mix up/stir or whip any grease into them. Filling all the empty space is a huge WASTE of grease that will just gets scooped out next time ya repack them.

Now the 5 ball or birfields are a different story. Those like grease. But even those kinda just push it out of the way and then run dry anyways.

99 percent of the time the crappy axle seals just let all the 90wt run into the knuckles anyways making it all the soupy consistency of #1 grease. But that usually only happens if you offroad a bunch or leave the rig parked on a side hill.


Just my .02

I have to keep reminding myself that these trucks were designed well before I was born, and even the shittiest lubes these days are 10x better than the most expensive stuff they had back then.

I ended up with a 5 gallon pail of lithium complex, extreme pressure, no moly, NLGI GC-LB, NLGI 2 for $134 before tax.

Most of the military axles I have torn down had a clear/whitish kinda grease that was VERY waxy in the bearings. Must be some kinda super water resistant grease. The bearings were always in great shape tho.

I always watched for years for a can of that grease to come through the scrap, but it never did.

2mpg 1gpm

Calculating the exact time it would take for a person to consume enough oxygen or exhale enough carbon dioxide to make the environment unsuitable for respiration in a sealed room is a complex task that depends on several variables, including the person's metabolic rate, lung capacity, and the initial concentration of oxygen in the room. However, I can provide a rough estimate based on some general assumptions.

1. **Volume of the Room:** The room's volume is 7' x 12' x 7' = 588 cubic feet (assuming you're talking about a room with standard atmospheric pressure and temperature).

2. **Oxygen Consumption:** On average, a person at rest consumes about 250 milliliters (ml) of oxygen per minute. For simplicity, we'll assume this person is at rest.

3. **Carbon Dioxide Production:** A person exhales about 200 ml of carbon dioxide per minute at rest.

4. **Initial Oxygen Concentration:** We'll assume the room starts with a normal atmospheric oxygen concentration of about 21%.

Now, let's calculate how long it would take for a person to deplete the oxygen in the room to a level that becomes dangerous (below 18%) and accumulate enough carbon dioxide to be harmful (above 5%).

- The room volume is 588 cubic feet.
- Initial oxygen volume in the room: 588 cubic feet x 0.21 (21%) = 123.48 cubic feet of oxygen.

Let's calculate the time it takes for the person to consume this initial oxygen volume:

\(Time_{oxygen} = \frac{Initial\;Oxygen\;Volume}{Oxygen\;Consumption\;Rate} = \frac{123.48\;cubic\;feet}{0.25\;cubic\;feet/min} = 493.92\;minutes\)

So, it would take approximately 493.92 minutes or about 8 hours and 14 minutes for a person at rest to consume enough oxygen to lower the oxygen concentration in the room to a potentially dangerous level.

Now, let's calculate how long it takes for the person to produce enough carbon dioxide to reach a potentially harmful concentration:

- Initial carbon dioxide volume in the room: 0 cubic feet (assuming the room starts with no carbon dioxide).

\(Time_{CO2} = \frac{Room\;Volume \times CO2\;Threshold\;Concentration}{CO2\;Production\;Rate}\)

\(Time_{CO2} = \frac{588\;cubic\;feet \times 0.05}{0.2\;cubic\;feet/min} = 147\;minutes\)

It would take approximately 147 minutes or about 2 hours and 27 minutes for a person to produce enough carbon dioxide to reach a potentially harmful concentration.

Therefore, it would take longer for oxygen depletion to become a concern than for carbon dioxide buildup in this scenario. However, please note that these calculations are based on simplified assumptions and actual results could vary significantly depending on many factors, including the person's activity level, health, and the initial room conditions. In reality, oxygen levels below 18% and carbon dioxide levels above 5% are already dangerous and can lead to unconsciousness or death. It's essential to prioritize safety and ensure proper ventilation in enclosed spaces.